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y^2-11y-5.25=0
a = 1; b = -11; c = -5.25;
Δ = b2-4ac
Δ = -112-4·1·(-5.25)
Δ = 142
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{142}}{2*1}=\frac{11-\sqrt{142}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{142}}{2*1}=\frac{11+\sqrt{142}}{2} $
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